(2x-5)(x^2+6x-4)=0

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Solution for (2x-5)(x^2+6x-4)=0 equation:


Simplifying
(2x + -5)(x2 + 6x + -4) = 0

Reorder the terms:
(-5 + 2x)(x2 + 6x + -4) = 0

Reorder the terms:
(-5 + 2x)(-4 + 6x + x2) = 0

Multiply (-5 + 2x) * (-4 + 6x + x2)
(-5(-4 + 6x + x2) + 2x * (-4 + 6x + x2)) = 0
((-4 * -5 + 6x * -5 + x2 * -5) + 2x * (-4 + 6x + x2)) = 0
((20 + -30x + -5x2) + 2x * (-4 + 6x + x2)) = 0
(20 + -30x + -5x2 + (-4 * 2x + 6x * 2x + x2 * 2x)) = 0
(20 + -30x + -5x2 + (-8x + 12x2 + 2x3)) = 0

Reorder the terms:
(20 + -30x + -8x + -5x2 + 12x2 + 2x3) = 0

Combine like terms: -30x + -8x = -38x
(20 + -38x + -5x2 + 12x2 + 2x3) = 0

Combine like terms: -5x2 + 12x2 = 7x2
(20 + -38x + 7x2 + 2x3) = 0

Solving
20 + -38x + 7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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